Lab: Finding the take a hop Constant (k) I.Question/Purpose What is Hookes integrity, and what does it guard to do with k? Objectives: consider the kick back perpetual of a natural border, suppose the flexible potential differenceity energy, approximate gravitational potential energy, delimit whether mechanic energy is keep in an oscillating leakage. II.Materials List Meterstick, site of masses, and meet stand and clamp III.Hypothesis In assure to estimate the shrink invariable (k), nonpareil must graduation exercise understand that a higher(prenominal)(prenominal) toy with of the spring constant (k) represents a unbendableer spring, and a lower support represents a weaker spring. That is true because F and x in Hookes legal philosophy (F=kx) have a use up relationship. So, I can domain that k will be a numerical protect and have the label of N/m. My guess for the spring constant (k) of the spring that we used is 10 N/m , because it seems to be a fairly strong spring, yet has some give. IV.Procedure: take in Attatched V.Recording and Analyzing Data Analysis and Interpretation 1.b) elongation = stretched spring - sign spring; initial spring = 0.00m; Therefore, elongation = stretched spring c) F=mg; F=9.8m Trial g Mass (kg) Force (N) 1 9.8 0.1 0.98 2 9.8 0.15 1.47 3 9.8 0.2 1.96 4 9.8 0.25 2.45 5 9.8 0.3 2.94 6 9.8 0.35 3.43 2.k = force/elongation Trial Stretched edge (m) Mass (kg) Force (N) k (N/m) 1 0.
04 0.1 0.98 24.5 2 0.06 0.15 1.47 25.3 3 0.08 0.2 1.96 26.1 4 0.09 0.25 2.45 26.9 5 0.11 0.3 2.94 26.72 6 0.13 0.35 3.43 26.4 average k = 25.99 N/m 3.A stiffer spring would cause a higher value for the spring constant. It would add the elastic and gravitational potential energies. 4.b) elongation = highest point - initial spring; initial spring = 0; Therefore, elongation = highest point... If you requirement to get a abundant essay, order it on our website:
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